1 - 1/4 + 1/9 - 1/16 + ................. + 1/n²

// 1 - 1/4 + 1/9 - 1/16 + ................. + 1/n²
Program:
#include<stdio.h>
int main()
{
int n,i,sign=1;
float sum=0;
printf("Enter n: ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum=sum+(1.0/(i*i))*(sign);
sign=sign*(-1);
}
printf("sum= %f",sum);
return 0;

}

Output:


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