1 + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n)

// 1 + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n)
Program:

 #include<stdio.h>
int main()
{
int n,i,j,sum=0;
printf("Enter n: ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
sum=sum+j;
}
}
printf("sum= %d",sum);
return 0;
}

Output:

Labels:

No comments:

Post a Comment

Subscribe to: Post Comments (Atom)

x^y using recursion

Program: #include<stdio.h> int power(int a,int b); int main() { int x,y,ans; printf("Enter x and y:\n "); scanf(...

  • 1² + 2² +3² +.............+ n²
    // 1² + 2² +3² +.............+ n² Program: #include<stdio.h> int main() { int n,i,sum=0; printf("Enter n: "); sc...
  • Convert into upper string
    Program: #include<stdio.h> int main() { char s1[30],s2[30]; int i=0; printf("Enter a string: "); scanf("%s...
  • Number Pattern : 29
    Program: #include <stdio.h> int main() {     int i,j,n; printf("How many lines: "); scanf("%d",&n); ...