1³ + 2³ + 3³ +..............+ n³

// 1³ + 2³ + 3³ +..............+ n³
Program:

 #include<stdio.h>
int main()
{
int n,i,sum=0;
printf("Enter n: ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum=sum+(i*i*i);
}
printf("sum= %d",sum);
return 0;
}

Output:

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